Conditional Control Statement ? :

/*The easiest way to use conditional control statement*/ #include< stdio.h >#include< conio.h >void main() { int n; clrscr(); n%4==0 ? printf("Leap Year") : printf("Not Leap Year"); //OR //printf(n%4==0 ? "Leap Year" : "Not Leap Year"); getch(); }

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Switch Statement

/*WAP to print the four-days of week from monday to thrusday which works upon the choice as S,M,T,H using switch case*/ #include< stdio.h >#include< conio.h >void main() { char n; clrscr(); printf("Enter the Choice from Four Days...\n") printf("S = Sunday \n") printf("M = Monday \n") printf("T = Tuesday \n") printf("H = Thursday \n\n") scanf("%c",&n); switch(n) { case 'S': printf("Sunday"); break; case 'M': printf("Monday"); break; case 'T': printf("Tuesday"); break; case 'H': printf("Thursday"); break; default: printf("Out of Choice"); break; } getch(); }

Output is as :
Enter the Choice from Four Days...
S = Sunday
M = Monday
T = Tuesday
H = Thursday

S
Sunday

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Ladder if or else if statement

The marks obtained by a student in 5 different subjects are input through the keyboard. The student gets a division as per the following rules:

=> Percentage above or equal to 60 - First Division
=> Percentage between 50 and 59 - Second Division
=> Percentage between 40 and 49 - Third Division
=> Percentage less than 40 - Fail

Method: 1

/*Write a program to calculate the division obtained by the student. There are two ways in which we can write a program for this example. These methods are given below: */ //Method-1 #include< stdio.h >#include< conio.h >void main() { int eng,math,com,sci,ss,total; float per; clrscr(); printf("Enter Five Subjects Marks\n"); scanf("%d%d%d%d%d",&eng,&math,&com,&sci,&ss); total = eng + math + com + sci + ss ; printf("Toal Marks : %d",total); per = total * 100.00 / 500; printf("\n Percentage : %f", per); if(per >= 60) { printf("\n 1st Division"); } else if(per >= 50) { printf("\n 2nd Division"); } else if(per >= 40) { printf("\n 3rd Division"); } else { printf("\n Sorry Fail"); } getch(); }


Method: 2

//Method-2 #include< stdio.h >#include< conio.h >void main() { int eng,math,com,sci,ss,total; float per; clrscr(); printf("Enter Five Subjects Marks\n"); scanf("%d%d%d%d%d",&eng,&math,&com,&sci,&ss); total = eng + math + com + sci + ss ; printf("Toal Marks : %d",total); per = total * 100.00 / 500; printf("\n Percentage : %f", per); if(per >= 60) { printf("\n 1st Division"); } if(per >= 50 && per < 60) { printf("\n 2nd Division"); } if(per >= 40 && per < 50) { printf("\n 3rd Division"); } if(per < 40) { printf("\n Sorry Fail"); } getch(); }

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nested if statement

/*If the ages of Ram, sham and Ajay are input through the keyboard, write a program to determine the youngest of the three*/ #include< stdio.h >#include< conio.h >void main() { int ram,sham,ajay; clrscr(); printf("Enter the Three Ages of Ram,Sham and Ajay\n"); scanf("%d%d%d",&ram,&sham,&ajay); if(ram < sham) { if(ram < ajay) { printf("Ram is Youngest"); } else { printf("Ajay is Youngest"); } } else { if(sham < ajay) { printf("Sham is Youngest"); } else { printf("Ajay is Youngest"); } } getch(); }

Output is as :
Enter the three Ages of Ram,Sham and Ajay
14
17
19
Ram is Youngest

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if-else statement - C Programming

/*Any Number is input through the keyboard. write a program to find out whether It is and Odd Number or Even Number.*/

#include< stdio.h >#include< conio.h >void main() { int n; n=1; clrscr(); printf("Enter the Number"); scanf("%d",&n); if(n%2==0) { printf("This is Even Number"); } else { printf("This is Odd Number"); } getch(); }

Output is as :
Enter the Number
4
This is Even Number

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If Statement - C Programming

/*Any Number is input through the keyboard. write a If program.*/ #include< stdio.h >#include< conio.h >void main() { int n; n=1; clrscr(); //clrscr() is the function of #include< conio.h > header file which will clear previous output of program printf("Enter the Number"); scanf("%d",&n); if(n>0) { printf("It is If Statement"); } getch(); }

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